Optimal. Leaf size=192 \[ \frac{b \tan (c+d x) \left (a^2 (-(6 A-8 C))+9 a b B+b^2 (3 A+2 C)\right )}{3 d}+\frac{\left (6 a^2 b B+2 a^3 C+3 a b^2 (2 A+C)+b^3 B\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+a^2 x (a B+3 A b)-\frac{b^2 \tan (c+d x) \sec (c+d x) (6 a A-5 a C-3 b B)}{6 d}-\frac{b (3 A-C) \tan (c+d x) (a+b \sec (c+d x))^2}{3 d}+\frac{A \sin (c+d x) (a+b \sec (c+d x))^3}{d} \]
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Rubi [A] time = 0.371263, antiderivative size = 192, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {4094, 4056, 4048, 3770, 3767, 8} \[ \frac{b \tan (c+d x) \left (a^2 (-(6 A-8 C))+9 a b B+b^2 (3 A+2 C)\right )}{3 d}+\frac{\left (6 a^2 b B+2 a^3 C+3 a b^2 (2 A+C)+b^3 B\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+a^2 x (a B+3 A b)-\frac{b^2 \tan (c+d x) \sec (c+d x) (6 a A-5 a C-3 b B)}{6 d}-\frac{b (3 A-C) \tan (c+d x) (a+b \sec (c+d x))^2}{3 d}+\frac{A \sin (c+d x) (a+b \sec (c+d x))^3}{d} \]
Antiderivative was successfully verified.
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Rule 4094
Rule 4056
Rule 4048
Rule 3770
Rule 3767
Rule 8
Rubi steps
\begin{align*} \int \cos (c+d x) (a+b \sec (c+d x))^3 \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\int (a+b \sec (c+d x))^2 \left (3 A b+a B+(b B+a C) \sec (c+d x)-b (3 A-C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}-\frac{b (3 A-C) (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{1}{3} \int (a+b \sec (c+d x)) \left (3 a (3 A b+a B)+\left (3 A b^2+6 a b B+3 a^2 C+2 b^2 C\right ) \sec (c+d x)-b (6 a A-3 b B-5 a C) \sec ^2(c+d x)\right ) \, dx\\ &=\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}-\frac{b^2 (6 a A-3 b B-5 a C) \sec (c+d x) \tan (c+d x)}{6 d}-\frac{b (3 A-C) (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{1}{6} \int \left (6 a^2 (3 A b+a B)+3 \left (6 a^2 b B+b^3 B+2 a^3 C+3 a b^2 (2 A+C)\right ) \sec (c+d x)+2 b \left (9 a b B-a^2 (6 A-8 C)+b^2 (3 A+2 C)\right ) \sec ^2(c+d x)\right ) \, dx\\ &=a^2 (3 A b+a B) x+\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}-\frac{b^2 (6 a A-3 b B-5 a C) \sec (c+d x) \tan (c+d x)}{6 d}-\frac{b (3 A-C) (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac{1}{2} \left (6 a^2 b B+b^3 B+2 a^3 C+3 a b^2 (2 A+C)\right ) \int \sec (c+d x) \, dx+\frac{1}{3} \left (b \left (9 a b B-a^2 (6 A-8 C)+b^2 (3 A+2 C)\right )\right ) \int \sec ^2(c+d x) \, dx\\ &=a^2 (3 A b+a B) x+\frac{\left (6 a^2 b B+b^3 B+2 a^3 C+3 a b^2 (2 A+C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}-\frac{b^2 (6 a A-3 b B-5 a C) \sec (c+d x) \tan (c+d x)}{6 d}-\frac{b (3 A-C) (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}-\frac{\left (b \left (9 a b B-a^2 (6 A-8 C)+b^2 (3 A+2 C)\right )\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d}\\ &=a^2 (3 A b+a B) x+\frac{\left (6 a^2 b B+b^3 B+2 a^3 C+3 a b^2 (2 A+C)\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{A (a+b \sec (c+d x))^3 \sin (c+d x)}{d}+\frac{b \left (9 a b B-a^2 (6 A-8 C)+b^2 (3 A+2 C)\right ) \tan (c+d x)}{3 d}-\frac{b^2 (6 a A-3 b B-5 a C) \sec (c+d x) \tan (c+d x)}{6 d}-\frac{b (3 A-C) (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}\\ \end{align*}
Mathematica [B] time = 6.58619, size = 1335, normalized size = 6.95 \[ \text{result too large to display} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.078, size = 294, normalized size = 1.5 \begin{align*}{\frac{A{a}^{3}\sin \left ( dx+c \right ) }{d}}+{a}^{3}Bx+{\frac{B{a}^{3}c}{d}}+{\frac{{a}^{3}C\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+3\,{a}^{2}Abx+3\,{\frac{A{a}^{2}bc}{d}}+3\,{\frac{B{a}^{2}b\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+3\,{\frac{{a}^{2}bC\tan \left ( dx+c \right ) }{d}}+3\,{\frac{Aa{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{d}}+3\,{\frac{Ba{b}^{2}\tan \left ( dx+c \right ) }{d}}+{\frac{3\,Ca{b}^{2}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{3\,Ca{b}^{2}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{A{b}^{3}\tan \left ( dx+c \right ) }{d}}+{\frac{B{b}^{3}\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{2\,d}}+{\frac{B{b}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{2\,C{b}^{3}\tan \left ( dx+c \right ) }{3\,d}}+{\frac{C{b}^{3}\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.03056, size = 378, normalized size = 1.97 \begin{align*} \frac{12 \,{\left (d x + c\right )} B a^{3} + 36 \,{\left (d x + c\right )} A a^{2} b + 4 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C b^{3} - 9 \, C a b^{2}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 3 \, B b^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 6 \, C a^{3}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 18 \, B a^{2} b{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 18 \, A a b^{2}{\left (\log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, A a^{3} \sin \left (d x + c\right ) + 36 \, C a^{2} b \tan \left (d x + c\right ) + 36 \, B a b^{2} \tan \left (d x + c\right ) + 12 \, A b^{3} \tan \left (d x + c\right )}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.578599, size = 543, normalized size = 2.83 \begin{align*} \frac{12 \,{\left (B a^{3} + 3 \, A a^{2} b\right )} d x \cos \left (d x + c\right )^{3} + 3 \,{\left (2 \, C a^{3} + 6 \, B a^{2} b + 3 \,{\left (2 \, A + C\right )} a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (2 \, C a^{3} + 6 \, B a^{2} b + 3 \,{\left (2 \, A + C\right )} a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (6 \, A a^{3} \cos \left (d x + c\right )^{3} + 2 \, C b^{3} + 2 \,{\left (9 \, C a^{2} b + 9 \, B a b^{2} +{\left (3 \, A + 2 \, C\right )} b^{3}\right )} \cos \left (d x + c\right )^{2} + 3 \,{\left (3 \, C a b^{2} + B b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.37315, size = 591, normalized size = 3.08 \begin{align*} \frac{\frac{12 \, A a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1} + 6 \,{\left (B a^{3} + 3 \, A a^{2} b\right )}{\left (d x + c\right )} + 3 \,{\left (2 \, C a^{3} + 6 \, B a^{2} b + 6 \, A a b^{2} + 3 \, C a b^{2} + B b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 3 \,{\left (2 \, C a^{3} + 6 \, B a^{2} b + 6 \, A a b^{2} + 3 \, C a b^{2} + B b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (18 \, C a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 18 \, B a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 9 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 6 \, A b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 3 \, B b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 6 \, C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 36 \, C a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 36 \, B a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 12 \, A b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 4 \, C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 18 \, C a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 18 \, B a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 9 \, C a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 6 \, A b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 3 \, B b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 6 \, C b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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